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Heat Transfer
Heat conduction through walls and insulation, overall heat transfer, heat exchanger sizing, radiation and heating-up processes.
Heat Loss of an Insulated Pipe
Cylindrical heat conduction + outside heat transfer
Heat loss per meter q̇–
Total heat loss Q̇–
Surface temperature–
Comparison: without insulation*–
*Without insulation, same α, radiation neglected. The actual loss of bare pipes is usually even higher.
Theory
Heat flow per meter of pipe through a cylindrical insulation layer with outside heat transfer:q̇ = π · (Ti − Ta)ln(d₂/d₁)2·λ + 1α·d₂
- d₂ = d₁ + 2·s: outside diameter of the insulation
- λ: thermal conductivity (mineral wool ≈ 0.04 W/mK)
- α: outside heat transfer coefficient (still air ≈ 8–12 W/m²K)
- Inside heat transfer and the (steel) pipe wall are negligible.
Overall Heat Transfer of a Plane Wall (U-Value)
Up to 3 layers + surface heat transfer
U-value–
Heat flow Q̇–
Theory
The overall heat transfer coefficient U combines all individual thermal resistances:1U = 1αᵢ + Σ sⱼλⱼ + 1αₐ
Q̇ = U · A · ΔT
Typical α values:
- still air (inside): 8 W/m²K
- moving air (outside): 25 W/m²K
- flowing water: 500–4,000 W/m²K
- condensing steam: 5,000–10,000 W/m²K
Heat Exchanger (LMTD Method)
Required heat transfer area
Heat duty Q̇–
ΔT_log–
Required area A–
Theory
Sizing via the log mean temperature difference (LMTD):Q̇ = ṁ · cp · (Th1 − Th2)
ΔTlog = ΔT₁ − ΔT₂ln(ΔT₁ / ΔT₂)
A = Q̇U · ΔTlog
- Counterflow: ΔT₁ = Th1−Tc2, ΔT₂ = Th2−Tc1
- Parallel flow: ΔT₁ = Th1−Tc1, ΔT₂ = Th2−Tc2
- For the same heat duty, counterflow needs less area.
Thermal Radiation
Stefan-Boltzmann law
Radiant heat flux q̇–
Radiant power Q̇–
Theory
Net radiation from a body to its surroundings:Q̇ = ε · σ · A · ( T₁⁴ − T₂⁴ )
σ = 5.67·10⁻⁸ W/m²K⁴ (temperatures in kelvin!). Emissivities:
- black body: 1.0
- oxidized steel: ≈ 0.8
- painted surface: ≈ 0.9
- polished aluminum: ≈ 0.05
Heating Up / Cooling Down
Amount of heat and heating power
Amount of heat Q–
Q–
Required heating power P–
Theory
Amount of heat needed to raise the temperature:Q = m · c · (T₂ − T₁)
Required heating power for a desired heating time t:
P = Qt · η
- η accounts for losses (insulation, transfer)
- 1 kWh = 3,600 kJ
- Rule of thumb: heating 1 m³ of water by 1 K takes ≈ 1.16 kWh
Rough estimate for preliminary design. Does not replace a code-compliant design calculation.